Math, asked by nihalanikhushi5, 8 months ago

find the perimeter of a triangle having sides 3⅓,2 3/5,¼​

Answers

Answered by aroy54547
3

Answer:

Perimeter of Triangle=1st side+2nd side+3rd side

1st side=3⅓=10/3

2nd side=2 3/5=13/5

3rd side=¼

Perimeter=10/3+13/5+¼

L.C.M=60

(10×20)+(13×12)+(15×1)/60

=200+156+15/60

Answer=371/60m or 6 11/60

HOPE IT HELPS ✌️✌️✌️.

Answered by gkashika13
0

Hey there! Here is your answer:

The Perimeter of the triangle:

Side1 + Side2 + Side3

=10/3 + 13/5 + 1/4

= Lcm = 60

= 200/60 + 156/60 + 15/60

=371/60

Therefore, the perimeter of the triangle is 371/60 cm.

Hope it helps! Brainliest pls! Good day!

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