find the perimeter of a triangle if one side is 11 cm and other side is one fifth of the parameter and the third side is one fourth of the parameter
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here, side a=11 b=1/5x c=1/4x
perimeter of triangle=a+b+c
=11+1/5x+1/4x
11+4+5/20x
11+9/20x
9/20x= -11
x= -11×20/9
x= -220/9
x= -24.4
perimeter of triangle=a+b+c
=11+1/5x+1/4x
11+4+5/20x
11+9/20x
9/20x= -11
x= -11×20/9
x= -220/9
x= -24.4
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