Question

Find the perimeter of a triangle whose length and breadth are

given by expression 2x+15 and x+8.​

Answer 1

Correct Question:

Find the perimeter of a rectangle whose length and breadth are given by expression 2x + 15 and x + 8.

Given:

✰ Length of the rectangle = 2x + 15 units

✰ Breadth of the rectangle = x + 8 units

To find:

✠ The perimeter of a rectangle.

Solution:

❖ By using formula to calculate perimeter of a rectangle, and putting the values of length of the rectangle and breadth of the rectangle, we will find the perimeter of a rectangle.

Let's find it!

Perimeter of rectangle = 2 ( length + breadth )

➤ Perimeter of rectangle = 2 ( l + b )

➤ Perimeter of rectangle = 2 ( 2x + 15 + x + 8 )

Now, add the terms first. First add coefficients of x and then constant terms separately.

➤ Perimeter of rectangle = 2 ( 3x + 15 + 8 )

➤ Perimeter of rectangle = 2 ( 3x + 23 )

Now, multiply two by each,

➤ Perimeter of rectangle = 6x + 46 units

∴ Perimeter of rectangle = 6x + 46 units

Now, if we need to find area?

Area of rectangle = length × breadth sq. units

➤ Area of rectangle = l × b sq. units

➤ Area of rectangle = ( (2x + 15) × (x + 8))

➤ Area of rectangle = ( 2x(x + 8) + 15(x + 8))

➤ Area of rectangle = 2x² + 16x + 15x + 120

➤ Area of rectangle = 2x² + 31 + 120

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