Question

find the perimeter of a triangle whose length is 40 and diagonal is 41 ​

Answer 1

Answer:

let ABCD be rectangle.

Then AC will be diagonal. And angle B = 90.

Length(BC) = 40 cm

diagonal(AB) = 41 cm

By using pythagoras theorem, we have:-

41²   = 40² + breadth²

1681 = 1600 + breadth²

1681 - 1600 = breadth²

breadth² = 81

breadth = √81

= 9cm

Now, Perimeter of rectangle = 2(L+B) = 2(BC+ AB)

                                        = 2(9 + 40) = 2(49)

                                        = 98 cm