Find the perimeter of a triangle whose sides are 2a+3b,b-a, 4a-2b.
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Answered by
1
perimeter of a triangle=sum of all sides
2a+3b+b-a+ 4a-2b
2a-a+4a+3b+b-2b
5a+2b
hope it's helpful for you
Answered by
3
Answer:
5a+2b
Step-by-step explanation:
side 1 = 2a +3b
side 2 = b-a
side 3 = 4a-2b
perimeter of triangle = side 1 + side 2 + side 3
= (2a+3b)+( b-a)+(4a-2b)
= (2a-a+4a)+ (3b+b-2b)
= 5a+2b
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