Math, asked by rohitreddy130, 9 hours ago

Find the perimeter of a triangle whose sides are 2a +3b,b-a, 4a-2b.​

Answers

Answered by Sathwikkayala
1

Answer:

5a+2b

Step-by-step explanation:

  • The perimeter is the sum of the sides of the polygon.
  • Here, the sides are (2a+3b), (b-a) and (4a-2b).
  • Adding the sides:
  1. (2a+3b)+(b-a)+(4a-2b)
  2. 2a+3b+b-a+4a-2b
  3. 2a-a+4a+3b+b-2b
  4. 2a+4a-a+3b+b-2b
  5. 5a+2b

So, the perimeter of this triangle is 5a+2b.

Hope this helps... Thank you for viewing my answer!

Answered by notagamerff
1

Answer:

5a+b

Step-by-step explanation:

2a+3b,b-a,4a-3b. perimeter = sum of all sides

=2a-a+4b+3b+b-3b

=5a+b

Hence, perimeter = 5a+b

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