find the perimeter of a triangle whose sides are 2x²+3x+1, x²+7 and 3x²-2x+3
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Answered by
1
2x^2+3x+1+x^2+7+3x^2-2x+3
6x^2+x+11
Answered by
1
Answer:
P = 6x² + 1x + 11
Step-by-step explanation:
perimeter of triangle = is the sum of the 3 sides
so,
2x² + 3x + 1
x² + 0x + 7
3x² - 2x + 3
= 6x² + 1x + 11
plz mark thanks and brainliest
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