Question

Find the perimeter of a triangle whose sides are 2y+3z, z-y and 4y-2z.​

Answer 1

Answer:

The answer is $5y+2z$

Step-by-step explanation:

Given side lengths are $2y+3z,z-y$ and $4y-2z$

Thus perimeter $=(2y+3z)+(z-y)+(4y-2z)$

                          $=2y+3z+z-y+4y-2z\\=(2y-y+4y)+(3z+z-2z)\\=5y+2z$, combine like terms

Answer 2

Answer:

5y+2z

Step-by-step explanation:

The  Perimeter of triangle is sum of all side

=(2y+3z+z−y+4y−2z)

=(5y+2z)

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