Question

Find the perimeter of a triangle whose sides are 5.4 cm, 4.6 cm and 6.8 cm.

2. Find the area of square whose perimeter is 84 cm.

3. The length and breadth of a rectangular field are 240 m and 180 m respectively. It is fenced with three rounds of a rope. Find the length of the rope.

Answer 1

Step-by-step explanation:

1) Perimeter of a triangle = a+b+c

= 5.4+4.6+6.8

=16.8

2) Area= side^2

side =perimeter/4

=84/4

=21

area=21^2

=441 cm^2

3) Perimeter of rectangle= 2(240+180)= 2(420)=840 m

As the rope is fencing the field three times we should multiply the perimeter of the field with 3,i.e, 840 ×3= 2520 m

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Answer 2

Question 1.

Given:

A triangle with:

• First side = 5.4 cm
• Second side = 4.6 cm
• Third side = 6.8 cm

To find:

The perimeter

Solution:

Perimeter of triangle = sum of three sides

⇒ Perimeter = 5.4 cm + 4.6 cm + 6.8 cm

⇒ Perimeter = 16.8 cm

∴ Perimeter of triangle is 16.8 cm.

Question 2.

Given:

A square with

• Perimeter = 84 cm

To find:

The area

Solution:

Perimeter of square = 4 × side

⇒ 84 cm = 4 × side

⇒ $\dfrac{84}{4}=\sf{side}$

⇒ 21 cm = side

Area of square = (side)²

⇒ Area = 21²

⇒ Area = 441 cm²

∴ Area of square is 441 cm².

Question 3.

Given:

A rectangle field with:

• Length = 240 m
• Breadth = 180 m

To find:

Length of the rope

Solution:

Perimeter of the rectangle = 2(l + b)

⇒ Perimeter = 2(240 + 180)

⇒ Perimeter = 2(420)

⇒ Perimeter = 840 m

Length of the rope = 3 × Perimeter

⇒ Length of the rope = 3 × 840 m

⇒ Length of the rope = 2520 m

∴ Length of the rope is 2520 m.