Question

find the perimeter of a triangle whose sides are 8cm, 10cm and 14 cm ​

Answer 1

8cm+10cm+14cm

32cm is the answer

Answer 2

Answer:

32 would be the correct answer

Given sides of triangle are :

a = 8cm b = 10cm c = 14cm

$\: s \ = \frac{a + b + c}{2} = \frac{8 + 10 + 14}{2} = \frac{32}{2}$

$\: (s - a) = \frac{32}{2} - 8 = \frac{32 - 16}{2} = \frac{16}{2}$

$\: (s - b) = \frac{32}{2} - 10 = \frac{32 - 20}{2} = \frac{12}{2}$

$\: (s - c) = \frac{32}{2} - 14 = \frac{32 - 28}{2} = \frac{4}{2}$

$\: area = \: \sqrt{s \: (s - a ) \: (s - b) \: (s - b)}$

$\: \: \: \: = \sqrt{ \frac{32}{2} \times \frac{16}{2} \times \frac{12}{2} \times \frac{4}{2} }$

$\: \: \: \: = \sqrt{ \frac{24576}{16} } = \frac{9.797}{4} = 2.449 {cm}^{2}$

Step-by-step explanation:

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