Question

Find the perimeter of a triangle whose vertices are(0,0) (a,0) and (0,b). ​

Answer 1

Answer:

Step-by-step explanation:

We have to add the distances of all the 3 sides

SO

for first side let x1=0,x2=a And y1=0,y2=0 the distance =a using formula$root over((x2-x1)^2+(y2-y1)^2)$

similarly second side=rootover(a^2+b^2)

thord side =b

then perimeter =a+rootover(a^2+b^2)+b

Answer 2

Answer:

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