Question

Find the perimeter of a triangle whose vertices are (0 4) (0 0) and (3 0)

Answer 1

first find length of each sides of ∆  

Let A( 4 , 0) B(0, 0) and C (0 , 3)  

use distance formula,  

AB =√(4²+0) =4  

BC= √(0+3²) = 3

CA =√(4²+3²) =5  

now ,

perimeter of ∆ = 3 + 4 + 5= 12 unit