Question

Find the perimeter of a triangle whose vertices are P (8,0), Q (0,0) and R (6,0). ​

Answer 1

Given :-

Vertices of triangle are P ( 8 , 0 ), Q ( 0 , 0 ) and R ( 6 , 0 ).

To Find :-

Perimeter of triangle PQR.

Solution :-

First lets find PQ, QR and PR.

$\boxed{\bf Distance \ formula = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$

$\bullet \sf \ PQ = \sqrt{(8-0)^2+(0-0)^2}$

        $= \sf \sqrt{8^2+0} \\\\= \sqrt{64} \\\\= 8 \ units$

$\bullet \sf \ QR = \sqrt{(6-0)^2++(0-0)^2}$

        $= \sf \sqrt{6^2+0} \\\\= \sqrt{36} \\\\= 6 \ units$

$\bullet \ \sf PR = \sqrt{(8-6)^2+(0-0)^2}$

       $= \sf \sqrt{2^2+0} \\\\= \sqrt{4} \\\\= 2 \ units$

Perimeter of triangle PQR = PQ + QR + PR

                                           = 8 + 6 + 2

                                           = 16 units