Math, asked by sunilpotdar1207, 7 months ago

Find the perimeter of a triangle whose vertices have the coordinates (3,10) (5,2)&(4,12).

Answers

Answered by shauryaasthana2604
1

Answer:

perimeter of triangle=

along x coordinate

x= (3+5+4)/3

x=4

along y axis,

y = (10+2+12)/3

y = 8

(x,y)=(4,8)

Similar questions