Question

FIND THE PERIMETER OF A TRIANGLE
WITH SIDES
3x2 + 2x, 4x-3, AND x2 - 4x.​

Answer 1

Answer:

2x+3x-10

Step-by-step explanation:

Let the third side be a.

Perimeter = Sum of side

x^2-2x+1+3x^2-5x+3+a = 6x^2-4x+9

x^2+3x^2-6x^2x-5x+4x+1+9+a=0

-2x^2-3x+10-a=0

2x^2+3x-10-a=0

a=2x^2+3x-10

Therefore the third side is 2x+3x-10