Question

find the perimeter of a triangle with sides 3z-2x-y,4x+y-2z and x+y+z. class 7, subject maths.
plz this question ans step by step .​

Answer 1

Given that -

✠ 1st side of triangle = 3z - 2x - y

✠ 2nd side of triangle = 4x + y - 2z

✠ 3rd side of triangle = x + y + z.

To find -

✠ Perimeter of triangle.

Solution -

✠ Perimeter of triangle = +2z + 3x + 2y

Using concept -

Formula to find perimeter of triangle.

Using formula -

Perimeter of triangle = a + b + c

Where,

☃️ a denotes 1st side

☃️ b denotes 2nd side

☃️ c denotes third side

Full solution -

~ Let us put the values according to the using formula..!

⇢ Perimeter of triangle = a + b + c

⇢ Perimeter of triangle = (3z - 2x - y) + (4x + y - 2z) + (x + y + z)

⇢ Perimeter of triangle = +2z + 3x + 2y

Working note - (Below or attachment)

+3z - 2x - 1y

-2z + 4x + 1y

-1z + 1x + 1y

___________

+2z + 3x + 2y

___________

Answer 2

Answer:

Perimeter of a triangle

=sum of its sides

=(2y+3z+z−y+4y−2z)

=(5y+2z)