Question

Find the perimeter of a triangle with sides 7 1/6 cm,3 2/3 cm and 5 1/6 cm​

Answer 1

Answer:

Given :

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)( 3,3)\qbezier(5,0)(5, 0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.8,3.2){ \sf A \;\; 7 \dfrac{1}{6} cm }\put(-0.4,-0.2){ \sf 5 \dfrac{1}{6} cm\;\; C }\put(5.1, - 0.3){ \sf B \;\;\;\; 3\dfrac{2}{3} cm }\end{picture}$

$\sf{\angle{A}=7\dfrac{1}{6}cm}$

$\sf{\angle{B}=3\dfrac{2}{3}cm}$

$\sf{\angle{C}=5\dfrac{1}{6}cm}$

To find :

$\textsf{The perimeter of the triangle}$

Taken :

To find the perimeter of the triangle use the formula of triangle :

$\sf\boxed{P=\angle{A}+\angle{B}+\angle{C}}$

Where ,

P = Perimeter of the triangle

Solution :

$\sf:\implies{P=7\dfrac{1}{6}+3\dfrac{2}{3}+5\dfrac{1}{6}}$

Now , first make the mixed fraction in the improper fraction .

$\sf:\implies{P=\dfrac{43}{6}cm+\dfrac{11}{3}cm+\dfrac{31}{6}cm}$

So , now we have converted mixed fraction into improper fraction.

Now , the L.C.M of 6 , 3 and 6 is 6 .

$\sf:\implies{P=\dfrac{43+22+31}{6}cm}$

$\sf:\implies{P=\dfrac{\cancel{96}}{\cancel{6}}cm}$

Now , make it in the simplest form .

$\sf:\implies{P=\dfrac{16}{1}cm}$

$\sf:\implies{P=16\:cm}$

Answer :

So , the perimeter of the triangle is 16 cm .

Answer 2

Answer:

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