Question

find the perimeter of a triangle with vertices (0,1),(0,0) and(1,0).

Answer 1

hey..

perimeter of triangle = 1 + 1 +
$\sqrt{2}$
= 2 +
$\sqrt{2}$

Answer 2

Hello mate,

If we draw the triangle with vertices (0,1),(0,0),(1,0),

Then, we get that the height of the triangle is 1 units and the base is also 1 unit,

so,The area of the triangle =1/2*base*height

=1/2*1 unit*1 unit=0.5 unit square,

Thanks for questioning

and,Please mark me as brainliest..