Find the perimeter of a triangle with vertices (0,4),(0,0) ,(3,0)
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Hey mate
Here goes your answer
Let A(0,4),B(0,0)and C(3,0)
By distance formula
AB = √(0-4)^2+(0-0)^2
AB=√16
AB=4
BC=√(0-3)^2+(0-0)^2
BC=√9=3
AC=√(0-4)^2+(0-3)^2
AC=√16+9
AC=√25=5
By heron's formula-------
=√6(6-5)(6-4)(6-3)
=√6*1*2*3
=√6*6
=6 unit sq is your answer.
Hope it helps you
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