find the perimeter of a triangle with vertices (0,4),(0,0) and (3,0)
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Answered by
3
First find length of each sides of ∆
Let A( 4 , 0) B(0, 0) and C (0 , 3)
use distance formula,
AB =√(4²+0) =4
BC= √(0+3²) = 3
CA =√(4²+3²) =5
now ,
perimeter of ∆ = 3 + 4 + 5= 12 unit
Let A( 4 , 0) B(0, 0) and C (0 , 3)
use distance formula,
AB =√(4²+0) =4
BC= √(0+3²) = 3
CA =√(4²+3²) =5
now ,
perimeter of ∆ = 3 + 4 + 5= 12 unit
Answered by
2
hii
here is your answer
area of triangle
1/2 ×b×h
1/2×3×4
=6
hope it helps
here is your answer
area of triangle
1/2 ×b×h
1/2×3×4
=6
hope it helps
prachi125:
your answer is wrong ya right
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