Question

find the perimeter of a triangle with vertices (0,4), (0,0,) ,and (3,0)

Answer 1

Heya user ,
Here is your answer !!

The three vertices are A (0,4) ; B (0,0) and C (3,0) .

So ,
length of AB = 4
length of BC = 3
length of CA = Sq. root of ( 4^2 + 3^2)
= Sq. root of ( 16 + 9 )
= Sq. root of 25
= 5 .

So , perimeter of ABC
= AB + BC + CA
= 5 + 4 + 3
= 12 ........... [Ans]

Hope it helps !!

Answer 2

Hello! dear,

Your answer goes like this..

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Initially,We should have to find the length of each of each sides of a Triangle.
So, A[0,4] B[0,0] C[3,0]

So we should use the distance formula I.e:--
AB⇒√[4²+0]=4
BC⇒√[0+3²]=3
CA⇒√[4²+3²]=5

So,We got the perimeter of the triangle.

Hence,Perimeter of Triangle =4+3+5=12 Units.

Hope It helps you dear.