Question

find the perimeter of a triangle with vertices (0,9) (0,0) ( 12,0)​

Answer 1

Answer:First find length of each sides of ∆

Let A( 4 , 0) B(0, 0) and C (0 , 3)

use distance formula,

AB =√(4²+0) =4

BC= √(0+3²) = 3

CA =√(4²+3²) =5

now ,

perimeter of ∆ = 3 + 4 + 5= 12 unit

hope it helps u

Step-by-step explanation:

Answer 2

Answer: 36

Step-by-step explanation:

(0,9) (0,0) (12,0) are the vertices . It forms a right-angled triangle whose 2 sides will be 9 units and 12 units. Use Pythagoras Theorem $p^{2} + b^{2} = h^{2}$ were p = perpendicular, b = base,  h = height.

So, $9^{2} + 12^{2} = h^{2}$ . From here, h = $\sqrt[2]{225}$ = 15 units.

So, the perimeter of triangle = 9+12+15 = 36 units