Question

find the perimeter of a triangles with the length of the three sides are (7x+5y-11z),(2x+3y+z) and (3x- y+7z)​

Answer 1

Answer:

$\huge{\boxed{\rm{\pink{P=12x+7y-3z}}}}$

Step-by-step explanation:

Given:-

A triangle with the length of the three sides are (7x+5y-11z),(2x+3y+z) and (3x- y+7z)

To find:-

Find the perimeter of a triangle with the length of the three sides are (7x+5y-11z),(2x+3y+z) and (3x- y+7z).

Using formula :-

If the three sides of a triangle is a,b,c units then the perimeter of the triangle is

sum of all sides= (a+b+c) units

Solution:-

The three sides of a triangle are (7x+5y-11z),(2x+3y+z) and (3x- y+7z)

Let a=(7x+5y-11z) units

b=(2x+3y+z) units

and c=(3x- y+7z) units

Perimeter of a triangle =Sum of all sides

=>a+b+c units

=>(7x+5y-11z)+(2x+3y+z)+(3x- y+7z)

=>7x+5y-11z+2x+3y+z+3x- y+7z

=>(7x+2x+3x)+(5y+3y-y)+(-11z+z+7z)

=> (12x+7y-3z ) units

Answer:-

Perimeter of the given triangle=(12x+7y-3z) units

Answer 2

Step-by-step explanation:

P=12x+7y-3z

Given:-

A triangle with the length of the three sides are (7x+5y-11z),(2x+3y+z) and (3x- y+7z)

To find:-

Find the perimeter of a triangle with the length of the three sides are (7x+5y-11z),(2x+3y+z) and (3x- y+7z).

Using formula :-

If the three sides of a triangle is a,b,c units then the perimeter of the triangle is

sum of all sides= (a+b+c) units

Solution:-

The three sides of a triangle are (7x+5y-11z),(2x+3y+z) and (3x- y+7z)

Let a=(7x+5y-11z) units

b=(2x+3y+z) units

and c=(3x- y+7z) units

Perimeter of a triangle =Sum of all sides

=>a+b+c units

=>(7x+5y-11z)+(2x+3y+z)+(3x- y+7z)

=>7x+5y-11z+2x+3y+z+3x- y+7z

=>(7x+2x+3x)+(5y+3y-y)+(-11z+z+7z)

=> (12x+7y-3z ) units

Answer:-

Perimeter of the given triangle=(12x+7y-3z) units

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