Question

Find the perimeter of AB=DC and BC=AD
<A=<B=<C=<D=90°​

Answer 1

Answer:

Hey mate

The figure is square .

and the perimeter of square is $side{}^{2}$

$\sf Side =\frac{x}{2}+{3}$

So,the area will be:-

$\sf (\frac{x}{2}+2){}^{2}$

Hope it's help uh