find the perimeter of ∆ABC If AB=512cm,BC=2 3/4cm and AC=3 3/5 cm.
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Answer:
pertimeter of triangle =a+b+c
512+23/4+33/5 BY LCM WE GET THAT 512+115+132/20
- 512+247/20
- 1024+247/20
- 10487/20 IS THE ANSWER
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