Question

Find the perimeter of ΔABC if its sidesare 5/ 6 cm, 4/12 cmand 5/ 18 cm.

Answer 1

$\sf\large\underline{\underline{\red{\sf Question}}}:$

• Find the perimeter of ΔABC, if its sides are 5/6 cm, 4/12 cm and 5/18 cm.

$\sf\large\underline{\underline{\red{\sf Solution}}}:$

$\green\bigstar\boxed{\mathfrak{Perimeter\green{_{\mathbb Triangle}}} = \textsf{Sum of all the sides}}$

so,

$\bf \sf\longmapsto Perimeter\green{_{triangle}} = \dfrac{5}{6}+\dfrac{4}{12}+\dfrac{5}{18}$

$\bf \sf\longmapsto Perimeter\green{_{triangle}} = \dfrac{5}{6}+\dfrac{1}{3}+\dfrac{5}{18}$

$\bf \sf\longmapsto Perimeter\green{_{triangle}} = \dfrac{5\times 3 + 1\times 6+5\times 1}{18}$

$\bf \sf\longmapsto Perimeter\green{_{triangle}} = \dfrac{15 + 6+5}{18}$

$\bf \sf\longmapsto Perimeter\green{_{triangle}} = \dfrac{26}{18}$

$\bf \sf\longmapsto Perimeter\green{_{triangle}} = \dfrac{13}{9}$

Hence,

• Perimeter of the triangle is 13/9 cm.

Answer 2

Answer :

• 7/6 cm

Given :

• Side A = 5/6 cm
• Side B = 4/12 cm
• Side C = 5/18 cm

To find :

• the perimeter of ΔABC

Solution :

⇒ Let's find the Perimeter of the Triangle.

$\sf \longrightarrow Perimeter = a + b + c$

$\sf \longrightarrow Perimeter = \dfrac{5}{6} + \dfrac{4}{12} + \dfrac{5}{18}$

$\sf \longrightarrow Perimeter = \dfrac{5}{6} + \dfrac{4}{12} + \dfrac{5}{18} \: [ \because LCM = 36]$

$\sf \longrightarrow Perimeter = \dfrac{5 \times 4}{6 \times 4} + \dfrac{4 \times 3}{12 \times 3 } + \dfrac{5 \times 2}{18 \times 2}$

$\sf \longrightarrow Perimeter = \dfrac{20}{36} + \dfrac{12}{36} + \dfrac{10}{36}$

$\sf \longrightarrow Perimeter = \dfrac{20 + 12 + 10}{36}$

$\sf \longrightarrow Perimeter = \dfrac{42}{36}$

$\sf \longrightarrow Perimeter = \dfrac{42 \div 6}{36 \div 6}$

$\sf \longrightarrow Perimeter = \dfrac{7}{6} \: cm$

• Therefore, the Perimeter of the ΔABC is 7/6 cm.