Question

find the perimeter of an equilateral triangle of area 16√3m²​

Answer 1

Answer:

Step-by-step explanation:

area of equilateral ∆=$\frac{\sqrt{3} a^{2} }{2}$

$16\sqrt{3} m^{2} = \frac{\sqrt{3} a^{2} }{2} \\\\16=\frac{a^{2}}{2}$∴√3 cancelled in both LHS & RHS

16×2=$a^{2}$

32=a²

$\sqrt{32} =a\\\\4\sqrt{2} =a$

now, we found that the measure of each side is 4√2 cm.

so,$Perimeter=3a\\=3(4\sqrt{2} )\\=12\sqrt{2} cm$

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