Question

Find the perimeter of an isosceles right angled triangle having an area of√100 cm.²​

Answer 1

Answer:

=> 2√10{1+√2}

Step-by-step explanation:

Given:

=> Isosceles triangle which has a right angle i.e. one of the angle is 90°

=> An isosceles triangle has 2 equal angles with 2 equal sides i.e.

=> Since in right angle triangle hypotenuse is greater than any of the side , so .. Base = Perpendicular = x (let)

We know , area of triangle =½× Height×Base

= > ½ × x² = √100 = 10

=> x² = 2×10

=> x = 2√5 cm

So, Base = Perpendicular= 2√5 cm

Hypotenuse = √{ Base² + perpendicular ²}

= √(20+20) = 2√10 cm

So,

perimeter of isosceles triangle = B+P+H

= 2√5 +2√5 + 2√10 cm

= 2√10 { 1 + √2} cm

Answer 2

Answer:

Area = 21 ×a×a= 2a 2 =100㎠

a=10 2 ㎝

Perimeter=2a+a 2

=20 2 +10×( 2 ) 2

=20( 2 +1)㎝

hope it helps you.