Question

Find the perimeter of an isosceles right angled
triangle with each of its congruent sides as 7 cm.
Complete the following activity to find the​

Answer 1

Answer:

Step-by-step explanation:

Let the other side of triangle is x cm

Then in isosceles right angle triangle two congruent sides are 7 cm

x  ^2 =(7)^2+(7)^2

x^2=49+49

x^2=198

x=7root 2

Then perimeter of right angle isosceles triangle =7+7+7root2=14+7root2​  

=7(2+root 2)

therefore answer is 7(2+root 2)cm

hope it helps u !!

Answer 2

Let the other side=x
by using Pythagoreas theorem
AC^2=AB^2+BC^2
x^2=7^2+7^2
x^2=49+49
x^2=98
x=7root2

Now the perimeter of the triangle = A+B+C
=7+7+7root2
=14+7root2
=7(2+root2)cm is the answer