Find the perimeter of an isosceles right angled triangle with each of its congruent sides as 7 cm.
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Answer:
49+7√2
Step-by-step explanation:
ab=bc=7cm
ac²=ab²+bc²
ac²=7²+7²
ac²=98
ac=√98
ab+bc+ca = perimeter of triangle abc
7+7+√98
49+√98
49+7√2
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