Find the perimeter of an isosceles right - angled triangles having an area of 5000m2. given √2=1.41how can I solved this question
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Answered by
0
let 2 sides = x
then area = 1/2×x×x= 5000
x = 100
now by Pythagoras theoram__
x²+x²= hypoyenuse)²
√20000 = hypoyenuse
100√2= hypoyenuse
100×1.41 = hypoyenuse
141 = hypoyenuse
now , perimeter = 100+100+141
= 341 ans.
then area = 1/2×x×x= 5000
x = 100
now by Pythagoras theoram__
x²+x²= hypoyenuse)²
√20000 = hypoyenuse
100√2= hypoyenuse
100×1.41 = hypoyenuse
141 = hypoyenuse
now , perimeter = 100+100+141
= 341 ans.
Answered by
1
perimeter of isosceles triangle= 2a+b
a= side of triangle
b= base of triangle
area of isosceles triangle =bh/2
b= base of triangle
h=height of triangle
By using this formula, u can solve this question
a= side of triangle
b= base of triangle
area of isosceles triangle =bh/2
b= base of triangle
h=height of triangle
By using this formula, u can solve this question
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