Question

find the perimeter of an isosceles triangle whose base is 10 cm and the length of each of the equal side is 12 centimetre​

Answer 1

Answer:

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Step 1: Solving for the altitude h

A = 1/2 bh

60 = 1/2 * 10 * h

60 = 5 * h

h = 12 cm

Step 2: Solving for the diagonal d

d^2 = (1/2b)^2 + h^2

d^2 = 5^2 + 12^2

d^2 = 25 + 144

d^2 = 169

d = 13 cm

Step 3: Solving for the perimeter of the isosceles triangle

P = base + diagonal 1 + diagonal 2

P = 10 cm + 13 cm + 13 cm

P = 36 cm

The perimeter of the isosceles triangle is 36 cm

Answer 2

Step-by-step explanation:

Perimeter of an isoceles ∆ = 2a + b

a represents the two equal sides

and b the unequal

Therefore,

➡ 2(12) + 10

➡ 24 + 10

➡ 34cm ans.