Find the perimeter of an isosceles triangle with base 3(x + 2) and the equal
sides 5(2x – 3).
Answers
Answered by
0
Answer:
Step-by-step explanation:
the perimeter of isosceles triangle = 32cm
p of isosceles triangle = 2 * equal side + base
let length of equal side be 3x and base be 2x
then
2 * 3x + 2x = 32 cm
6x + 2x = 32cm
8x = 32 cm
x= 4 cm
length of equal side = 3*4= 12cm
length of base = 2*4=8cm
area of isosceles triangle=b*1/4*√4a2-b2
= 8*1/4√4*144-64
=2√512
=2*22.62
= 45.25cm2
Answered by
0
Answer:
13x-9
Step-by-step explanation:
3(x+2)+5(2x-3)
3x+6+10x-15
13x-9....ans
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