Math, asked by diashah11, 2 months ago

Find the perimeter of an isosceles triangle with base 3(x + 2) and the equal
sides 5(2x – 3).

Answers

Answered by lakshmiprakash04
0

Answer:

Step-by-step explanation:

the perimeter of isosceles triangle = 32cm

p of isosceles triangle = 2 * equal side + base

let length of equal side be 3x and base be 2x

then

2 * 3x + 2x = 32 cm

6x + 2x = 32cm

8x = 32 cm

x= 4 cm

length of equal side = 3*4= 12cm

length of base = 2*4=8cm

area of isosceles triangle=b*1/4*√4a2-b2

= 8*1/4√4*144-64

=2√512

=2*22.62

= 45.25cm2

Answered by manushi0512
0

Answer:

13x-9

Step-by-step explanation:

3(x+2)+5(2x-3)

3x+6+10x-15

13x-9....ans

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