find the perimeter of an right isoscle triangle whoes one leg is 4✓2
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Step-by-step explanation:
perimeter is sum of all sides since it is isoceles traingle hence it's two side are equal and third side we can find through Pythagoras theorem hence let that side be x
(3√2)^2+(3√2)^2= x^2
18+18 =x^2
36=x^2
x= 6
perimeter will be 3√2+3√2+6= 6√2+6
6(√2+1)
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