Question

Find the perimeter of and area of the rectangle whose breath is 7cm and dignal is 25​

Answer 1

Answer:

Perimeter = 62 cm

Area = 168 (cm^2)

Step-by-step explanation:

Let Length = x

x^2 + 7^2 = 25 ^2

(Pythogoras theorem)

= x^2 = 25^2-7^2

= x^2 = 625 - 49

= x^2 = 576

x = Root of 576

x = 24

Perimeter of Rectangle

= 2(L+B)

= 2(7+24)

= 2(31)

= 62 cm

Area of Rectangle

= L×B (Sq.units)

= 7×24(cm^2)

= 168 (cm^2)

Answer 2

Step-by-step explanation:

breadth of rectangle = 7 cm

diagonal of rectangle= 25cm

therefore length of rectangle = √ (25^2 - 7^2)

= √(625-49)

= √576

= 24cm

Now perimeter of rectangle = 2(l+b)

= 2 ( 24cm + 7cm)

= 2×31 cm

= 62 cm

And Area of rectangle. =. l× b

= 24cm × 7 cm

= 168 square cm