Question

find the perimeter of (I) ∆ ABC (ii) the rectangle BCDE in this figure whose perimeter is grater​

Answer 1

$\huge\boxed{\underline{\bf { \red S \green O \pink L \blue U \orange T \purple I \red O \pink N \green{..}}}}$

$\large \red \bigstar \:\boxed{ \green{\bf Perimeter_{(triangle)} = AB + BE + AE}}$

Here

• AB = 5/2 cm
• BE = 2¾ = 11/4 cm
• AE = 3⅗ = 18/5 cm

$\longmapsto \sf Perimeter = \frac{5}{2} + \frac{11}{4} + \frac{18}{5}$

$\longmapsto \sf Perimeter = \frac{50 + 55 + 72}{20}$

$\longmapsto \sf Perimeter = \frac{177}{20} \: cm$

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$\large \red \bigstar \:\boxed{ \green{\bf Perimeter_{(rectangle)} = 2( L + B ) }}$

Here

• Length = 2¾ = 11/4 cm
• Breadth = 7/6 cm

$\longmapsto \sf Perimeter = 2 \bigg( \frac{11}{4} + \frac{7}{6} \bigg)$

$\longmapsto \sf Perimeter = 2 \bigg( \frac{33 + 14}{12} \bigg)$

$\longmapsto \sf Perimeter = 2 \bigg( \frac{47}{12} \bigg)$

$\longmapsto \sf Perimeter = \frac{47}{6} \: cm$

Triangle has more perimeter than rectangle