Question

Find the perimeter of isosceles trapeziam whose, equal sides are 4 cm in length and Sum of parallel sides is 10cm.

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Answer 1

Answer:REF.Image.

In isosceles trapezium, AD = BC

Let DC = 3a cm

⇒ AB = a cm

As sum of opposite sides is equal,

⇒AD+BC=4a⇒2AD=4a⇒AD=2a

Now perimeter = 16 cm ⇒8a=16⇒a=2cm

In △ALD,AL

2

=AD

2

−DL

2

(Pythagoras th.)⇒AL

2

=16−4=12

⇒AL=

12

​

=2

3

​

cm

Now, Area of trapezium =

2

1

​

(Sum of parallel sides)Height

=

2

1

​

(4a)(2

3

​

)

=2a×2

3

​

=4×2

3

​

=8

3

​

cm

2

Step-by-step explanation: