Question

Find the perimeter of rectangle if the length is 28 cm and its breadth is 48 cm.... ​

Answer 1

Given:

Length=28cm

Breadth=48cm

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To find?

Perimeter

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Solution:

Perimeter of a rectangle=2(l+b)

∴Perimeter of a rectangle=2(28+48)cm

∴Perimeter of a rectangle=2(76)cm

∴Perimeter of a rectangle=152cm

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D I A G R A M :

${\begin{gathered} \sf{28 \:cm}\huge\boxed{ \begin{array}{cc} \: \: \: \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \ \: \: \: \: \: \end{array}} \\ \: \: \: \: \: \sf{48 \: cm} \end{gathered}}$

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More formulas:-

❥Perimeter of a square=4×l

❥Perimeter of a rectangle=2(l+b)

❥Area of square=l^2

❥Area of rectangle=l×b

Answer 2

Perimeter of a rectangle=$\tt \pink{2(l+b)}$

∴Perimeter of a rectangle=$\tt \pink{2(28+48)}$

∴Perimeter of a rectangle=$\tt \pink{2(76)}$

∴Perimeter of a rectangle=$\tt \pink{152}$

Therefore perimeter of a rectangle is 152 cm..