Question

Find the perimeter of rectangle whose (a) Area=1050sqcm Length=35cm
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Answer 1

Answer:

area = l × b

1050 = 35 × b

30 = b

perimeter = 2(l+b)

= 2 ( 35 +30 )

= 130

Step-by-step explanation:

hope u better understand

Answer 2

    Solution      

Area of the rectangle = 1050 cm² .

Length (l) of the Rectangle = 35 cm

Breadth (b) = ?

We , know the formula for Area of a rectangle :-

Area of a rectangle = Length × Breadth

1050 = 35 × Breadth

$\sf Breadth = \dfrac{1050}{35}$

Breadth = 30 cm .

The Rectangle is

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 35cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 30 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Now , we have to find the perimeter of this rectangle.

Perimeter of rectangle = 2(l+b)

Here,

l = 35 cm

b = 30 cm

Perimeter = 2 ( 35 + 30 ) = 2 × 65 = 130 cm .

$\sf \boxed { \red Perimeter \: of \:the\: Rectangle = 130cm }$