Question

Find the perimeter of rectangle whose area is 600 M² and breadth 25 CM

Answer 1

Answer:

Perimeter of the rectangle is 4800.5 m.

Step-by-step explanation:

It is given that the area of the rectangle is 600 m^2 and breadth of the rectangle is 25 cm.

And, from the properties of rectangle we know that area of rectangle remains equal to the product of its length and breadth.

Thus,

= > 600 m^2 = 25 cm x length

= > 600 m^2 = 0.25 m x length

= > 600 m^2 / 0.25 m = length

= > 2400 m = length

Therefore,

Perimeter of the rectangle = 2( length + breadth )

                 = 2( 2400 m + 0.25 m )

                 = 2 ( 2400.25 m )

                 = 4800.5 m

Hence,

Perimeter of the rectangle is 4800.5 m.

Answer 2

$\huge\underline\mathfrak{Question-}$

Find the perimeter of rectangle whose area is 600 M² and breadth 25 CM.

$\huge\underline\mathfrak{Answer-}$

Given ;-
Area of Rectangle = 600 m²
Breadth = 25 cm

Here , Lenght is missing.

Now ,

=> 600 m² = Lenght × 25 cm
=> 600 m² = 0.25 m × 25 cm { 1 m = 100 cm }
=> Lenght = 600 m² ÷ 0.25 m
=> Lenght = 2400 m

Than ,

We know that ;-
Perimeter of Rectangle = 2 ( l + b )

=> 2 ( 2400 + 0.25 )m
=> 2 × 2400.25 m
=> 4800.50 m

Therefore ,
The Perimeter of the Rectangle = 4800.50 m