Question

find the perimeter of rectangle whose area is 600cm2 and breadth is 125 cm​

Answer 1

$\Large\bf{\color{blue}{\underline{\underline{Given:-}}}}$

$\bf Area \:of\: rectangle=600cm^2$

$\bf Breadth \:of\: rectangle=125cm$

$\Large\bf{\color{blue}{\underline{\underline{To\:Find:-}}}}$

$\bf perimeter\:of\: rectangle$

$\Large\bf{\color{blue}{\underline{\underline{Solution:-}}}}$

$\bf Area \:of\: rectangle=600cm^2$

$\bf {\underline{\boxed{\pink{Area\:of\: rectangle=Length×Breadth}}}}$

$\bf L×B=600$

$\bf L×125=600$

$\bf L=\dfrac{600}{125}$

$\bf {\boxed{L=4.8cm}}$

$\bf {\underline{\boxed{\pink{Perimeter\:of\: rectangle=2(l+b)}}}}$

$\bf :\implies 2(4.8+125)$

$\bf :\implies 2(129.8)$

$\bf :\implies {\underline{\boxed{\purple{259.6cm}}}}$