Question

Find the perimeter of rectangle whose breadth is 24cm and a diagonal is 25cm

Answer 1

Answer:

$breadth \: of \: rectangle = 24cm$

We know that, the diagonal of a rectangle divides it into two right angle traingle.

So, we can apply Pythagoras theorem.

$let \: us \: take \: base \: = 24 \: cm$

$and \: diagonal \: = \: hypotenuse \: = 25 \: cm$

Let's apply Pythagoras theorem

${hypotenuse}^{2} = \: \: {base}^{2} + {perpendicular}^{2}$

Now Put The Value

${25}^{2} = {24}^{2} + {perpendicular}^{2}$

$625 - 576 = {perpendicular}^{2}$

$49 = {perpendicular}^{2}$

$\sqrt{49} = perpendicular$

$7 = perpendicular$

So , Perpendicular = Length = 7

We know that.

Perimeter of Rectangle = 2(l +b)

$= 2(l + b)$

$= 2 (7 + 24)$

$= 2(31)$

$= 62 \: cm \: answer$

Hence the Perimeter of Rectangle is 62cm