Question

find the perimeter of rectangle whose (c) area =4800cm² breath =60cm ​

Answer 1

Answer:

The length will be 80 cm

so perimeter is 280 cm²

Hope it helps

Answer 2

Solution  

Area of the Rectangle = 4800 cm² .

Breadth (b) of the Rectangle = 60 cm .

Length (l) of the rectangle = ?

We, know the formula of Area of a rectangle.

Area of Rectangles = l × b

$\implies$ 4800 = l × 60

$\sf Length (l) = \dfrac{4800}{60} = 80 cm .$

The Required Rectangle is

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 80 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 60cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Now , we have to find the perimeter of the above Rectangle.

Perimeter of a rectangle  = 2 (l+b)

Perimeter of the rectangle = 2 (60 + 80) = 2 × 140 = 280cm .

$\sf \boxed { \red Perimeter \;of \;the \;Rectangle = 280 cm .}$