Question

find the perimeter of rectangle whose dimension are length 75m breadth 25m​

Answer 1

$\huge\sf\orange{an{\mathfrak{S}}wer:}$

${}$

$\bf{{\underline{Given}}:}$

• Length = 75m
• Breadth = 25m

$\bf{{\underline{To~find}}:}$

• The Perimeter of the rectangle

$\bf{{\underline{Solution}}:}$

$\sf Perimeter \: of \: a \: rectangle = 2(l + b) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf = 2(75 + 25) \\ \sf = 2(100) \: \: \: \: \: \: \: \: \\ \sf = \orange{ \underline{ \boxed{ \bf 200m}}} \: \: \: \: \: \:$

$\bf\therefore{{\underline{Required~answer}}:}$

• Perimeter of the rectangle is $\sf \orange{ \underline{ \boxed{ \bf 200m}}}$

Answer 2

Answer:

${\Large \bigstar \: \underline\frak\red{Given}}$

• ↝ Length of Rectangle = 75m
• ↝ Breadth of Rectangle = 25 m

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$\Large \bigstar \: \underline\mathfrak \red{To \: Find }$

• ↝ Primeter of Rectangle

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$\Large \bigstar \: \underline\frak\red{Using \: Formula }$

• ↝ Perimeter of Rectangle = 2(Lenght+Breadth)

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$\Large \bigstar \: \underline \frak \red{Solution}$

${: \implies\sf \pink{Perimeter \: of \: Rectangle} = \purple{2(Lenght+Breadth)}}$

${: \implies \sf \pink{Perimeter } = \purple{ 2(75 \: m+25 \:m)}}$

$: \implies\sf \pink{Perimeter }= \purple {2 \times 100}$

$:\implies\sf \pink{Perimeter} = \purple{200 \: m}$

$\Large \bigstar : \underline{\boxed{ \sf{ \purple{P}{\frak {\purple{erimeter} = \pink{200 \:m}}}}}} : \bigstar$

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$\Large \bigstar \: \underline \frak \red{Therfore}$

• The Perimeter of Rectangle is 200 m.

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$\large \bigstar \: \underline\frak \red{More \: Useful \: Formulae }$

${\leadsto\: \small\bf{Area \: of \: Rectangle =Length × Breadth}}$

${\leadsto \: \small \bf{Diagonal \: of \: Rectangle = \sqrt{ {Length }^{2} + { Breadth}^{2} }}}$

$\leadsto\: \small\bf{Area \: of \: Square } = {a}^{2}$

$\leadsto \: \small\bf{Perimeter \: of \: Square = 4a }$

$\leadsto\: \small\bf{Diagonal \: of \: Square = a \sqrt{2} }$