Question

find the perimeter of rectangle whose length and bredth are given by expression 2x+15 and x+8​

Answer 1

$\huge \mathfrak \blue {◤~Given~◢}$

A rectangle with length and breadth as 2x + 15 and x+8 is given.

$\huge \mathfrak \blue {◤~To~find~◢}$

We have to find the perimeter of the rectangle.

$\huge \mathfrak \blue {◤~Solution~◢}$

$\large \mathfrak \pink {\star~~Perimeter~of~a~rectangle=2(Length+Breadth)}$

$\pink \star \: \: \bf {2(2x + 15 + x + 8)}$

$\pink \star \: \: \bf2(3x + 23)$

$\pink \star \: \: \bf6x + 46 \: units$

☀️ Therefore, the perimeter of the rectangle with length 2x+15 and breadth x+8 is 6x+46 units.

$\huge \mathfrak \blue {◤~Know~more~◢}$

• Area of rectangle = Length × Breadth
• Area of a square = Side × Side
• Perimeter of a square = 4 × Side
• Area of a parallelogram = Height × Base

Answer 2

$ol:- 6x+46

Step-by-step explanation:

Length of a rectangle = 2x+15

Breadth of a rectangle = x+8

perimeter of rectangle = 2(l+b)

= 2(2x+15+x+8)

= 2(3x+23)

= 6x+46

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