Question

find the perimeter of rectangle whose length is 16 cm and diagonal is 20 cm
​

Answer 1

Answer:

Hope it helps dude

Step-by-step explanation:

Using the formulas

P=2(l+w)

d= √w²+l²

Solving  for P

P=2l+2√d²﹣l²

=2·16+2√20²﹣16²

=56cm

Answer 2

Question :-

Find the perimeter of rectangle whose length is 16 cm and diagonal is 20 cm

Answer :-

• Perimeter of rectangle = 56

Given :-

• length of rectangle ( l ) = 16cm

• Diagonal of rectangle ( d )= 20cm

To find :-

• Find the perimeter of rectangle = ?

Solution :-

Length = 16cm

Diagonal = 20cm

$\bf Breadth = \sqrt{ {(16)}^{2} - {(20)}^{2} } = \sqrt{256 - 400} = 12$

$\large\overline{\underline{ \boxed{ \sf \red{Formula \: used}}}}$

$\large\overline{\underline{ \boxed{ \bf {perimeter = 2(l + b)}}}}$

$\large \implies 2(16 + 12) = 56$

$\therefore$Perimeter of rectangle = 56