Question

Find the perimeter of rectangle whose length is 16 meter and length of diagonal is 20 meter.​

Answer 1

Step-by-step explanation:

length = 16m

diagonal = 20m

Since each angle of a rectangle = 90°

Acc. to Pythagoras Theorem

H² = P² + B² (diagonal² = length² + breadth²)

(20)² = (16)² + B²

B² = 20² - 16²

B² = 400 - 256

B = √(196)

Breadth = 14 cm

Perimeter = 2(l+b) = 2(16+14) = 2(30) = 60m

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Answer 2

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Given :-

• The length of rectangle is 16 meter.

• The length of diagonal is 20 meter.

To find :-

• The perimeter of rectangle.

Solution :-

Let A rectangle ABCD devided by digonal AC .

The length of rectangle is 16 meter.

• AB = 16m.

The length of diagonal is 20 meter.

• AC = 20m.

We know , in a rectangle all angles measures 90°.

In a triangle BAD , Using PGT

(AC)² = (BC)² + (AB)²

➝ (20)² = (BC)² + (16)²

➝ (20)² - (16)² = (BC)²

➝ 400 - 256 = (BC)²

➝ (BC)² = 144

➝ BC = √144

➝ BC = 12 m

The breadth of the rectangle is 12m.

The perimeter of the rectangle (P) = 2 ( l + b )

➝ 2 (AB + BC)

➝ 2 (16 + 12)

➝ 2 × 28

➝ 56

The perimeter of rectangle is 56 m.

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