find the perimeter of rectangle whose length is 24cm and diagonal is 25 cm
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Answered by
28
❗❗ Hey there ❗❗
Ur answer..
⤵⤵
Here,
Length = 24 cm.
Diagonal = 25 cm.
In a rectangle all the angles are 90 degree and the diagonal divides the rectangle into two right angled triangle.
So breadth is,
Breadth square = 25 square - 24 sqaure
= 49.
So breadth is 7 cm.
Now perimeter of Rectangle is =
= 2 ( l + b )
= 2 ( 24 cm + 7 cm )
= 2 ( 31 cm )
= 62 cm. ✔✔
HOPE IT WILL HELP..♡♡
plz mark as brainliest☺✌
Ur answer..
⤵⤵
Here,
Length = 24 cm.
Diagonal = 25 cm.
In a rectangle all the angles are 90 degree and the diagonal divides the rectangle into two right angled triangle.
So breadth is,
Breadth square = 25 square - 24 sqaure
= 49.
So breadth is 7 cm.
Now perimeter of Rectangle is =
= 2 ( l + b )
= 2 ( 24 cm + 7 cm )
= 2 ( 31 cm )
= 62 cm. ✔✔
HOPE IT WILL HELP..♡♡
plz mark as brainliest☺✌
jenjobybrainly:
Hi maheswota
Answered by
66
Condition - Given length of rectangle and Diagonal, Find breadth and then find perimeter .
When a diagonal cuts a rectangle it forms 2 right angled triangles, So by using Pythagoras theorem we will find breadth of the triangle (See the attached picture).
Finding AC in Δ ACD , By Pythagoras theorem
AD² = AC² + DC²
25² = AC² + 24²
625 = AC² + 576
AC² = 625 - 576
AC² = 49
AC =
AC = 7
Now we have found the breadth = 7 cm
Perimeter of a rectangle = 2 (L+B)
= 2 (24+7)
= 2 × 31
= 62
Hope it helps you :)
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