find the perimeter of rectangle whose length is 40 cm more than width
Answers
Answered by
1
let x be the breadth
length=x+40
area=x(x+40)
=x^2+40x unit^2
length=x+40
area=x(x+40)
=x^2+40x unit^2
Answered by
24
Answer:
Area = x(x+40)cm
= x² + 40x cm²
Hope it will be helpful ✌️
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