Question

Find the perimeter of rectangle whose length is 40cm and a diagonal is 41cm tell my answer don,t we slow​

Answer 1

Step-by-step explanation:

Given, length of a side is 40cm.

Length of diagonal is 41cm.

Let breadth be 'x' cm.

By Pythagoras theorem,

${41}^{2} = {40}^{2} + {x}^{2} \\ 1681 = 1600 + {x}^{2} \\ 81 = {x}^{2} \\ {x}^{2} = 81 \\ x = 9$

So, breadth is 9cm.

Perimeter is 2(l+b)=2(41+9)=2(50)=100cm.

Hence, perimeter is 100 cm.

Thank you

Answer 2

Step-by-step explanation:

Given:-length:-40 cm

diagonal:-41 cm

breadth:- x

According to question:-

by Pythagoras theorem:-

(h)^2=(b)^2+(p)^2

(41)^2=(x)^2+(40)^2

1681=(x)^2+1600

(x)^2= 1681-1600

(x)^2=81

x=√81

x=9 cm

i.e. breadth of rectangle= 9 cm

perimeter =2(l+b)

=2(40+9)

=2*49

=98 cm:- Ans

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